Mathematics - CTET Paper I Bengali (L1) & Odia (L2) Dec 2022 — Subject Test, Questions & Answers

Subject Test 2022 CTET Paper I Mathematics 30 questions 30 marks 30 min English and Bengali (বাংলা)

Mathematics - CTET Paper I Bengali (L1) & Odia (L2) Dec 2022 is a subject test in the CTET Paper I series on TG Exams, from 2022. It has 30 multiple-choice questions for 30 marks, with a 30-minute time limit. Every question is available in English and Bengali (বাংলা), with answer key and explanations. Sign up, unlock an exam pack and practise online.

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Sample questions with answers

A few questions from Mathematics - CTET Paper I Bengali (L1) & Odia (L2) Dec 2022. The full paper has 30 questions with detailed explanations after you sign in.

Q1. Karan every day before going to school searches for his things here and there. His mother said, 'why don't you develop a habit of putting your things at one place so that you will not have this nuisance of searching'. 'Habit' referred to by Karan's mother can be understood as
కరణ్ ప్రతిరోజు పాఠశాలకు వెళ్ళే ముందు తన వస్తువులను ఇక్కడ అక్కడ వెతుకుతాడు. అతని తల్లి, "నీ వస్తువులను ఒకే చోట పెట్టే అలవాటు ఎందుకు నేర్చుకోవు, దానివల్ల నీకు ఈ వెతికే బాధ ఉండదు" అని అన్నది. కరణ్ తల్లి సూచించిన 'అలవాటు'ను ఇలా అర్థం చేసుకోవచ్చు
  1. A driving force that helps us in paying attention / అవధానం వహించడంలో మనకు సహాయపడే శక్తి
  2. Ability of an individual to acquire a required degree of proficiency in a specific field / ఒక నిర్దిష్ట రంగంలో అవసరమైన స్థాయిలో నైపుణ్యాన్ని పొందగల వ్యక్తి సామర్థ్యం
  3. A particular feeling about something / ఏదో ఒకదాని గురించి ఒక నిర్దిష్ట భావన
  4. Behaviour so often repeated as to be automatic / స్వయం చాలకంగా మారేలా తరచుగా పునరావృతమయ్యే ప్రవర్తన (correct answer)
Answer: D
Q2. Identify the silent consonant letter in the word 'bridge'.
  1. b
  2. r
  3. d (correct answer)
  4. g
Answer: C
Q3. If x + y = 18 and x – y = 8 then 2x + 3y – xy =
x + y = 18 మరియు x – y = 8 అయితే, 2x + 3y – xy =
  1. 14 / 14
  2. –24 / –24 (correct answer)
  3. –16 / –16
  4. 20 / 20
Answer: B
Q4. If 3600 = 2^x * 3^y * 5^z, then (xy + yz + zx) / (x + y + z) =
3600 = 2^x * 3^y * 5^z అయితే, (xy + yz + zx) / (x + y + z) =
  1. 3 / 3
  2. 1 / 1
  3. 2 / 2 (correct answer)
  4. 4 / 4
Answer: C
Q5. To which 'Shatakam' (collection of verses) does the given poem belong?
ఇచ్చిన పద్యం ఏ శతకం లోనిది?
  1. Vemana / వేమన
  2. Sumathi / సుమతి (correct answer)
  3. Kumara / కుమార
  4. Neethi / నీతి
Answer: B

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